Question

A uniform meter stick is placed on and parallel to the x axis, with the 50 cm mark at the origin. It is pivoted at the 50 cm
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Solution : S.9IN 2.79N Taking tonque about the plust 0.48m | Tnet - CF-EF2 Orbiy = 5.91X0-02-2-7980•l! 10-11 m Thet = -0.1887

Add a comment
Know the answer?
Add Answer to:
A uniform meter stick is placed on and parallel to the x axis, with the 50...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A 9.9 kg stone is tied to a 6.2 m long string and swung around a...

    A 9.9 kg stone is tied to a 6.2 m long string and swung around a circle at a constant angular velocity 4.9. Calculate the magnitude of the torque about the origin. * A uniform meter stick is placed on and parallel to the x axis, with the 50 cm mark at the origin. It is pivoted at the 50 cm mark. A -6.61 N force is applied at the 13 cm mark, and a -3.02 N force is applied...

  • A uniform meter stick, mass is 0.2 kg, is able to rotate about an axis of...

    A uniform meter stick, mass is 0.2 kg, is able to rotate about an axis of rotation that passes through the 25 cm mark of the stick. The axis of rotation is parallel to the ground and perpendicular to the stick. There are also two small masses, each 0.5 kg, attached to the meter stick at the 0 cm mark and the 100 cm mark. 0 25 50 75 100 cm The stick is released from rest in the horizontal...

  • Torques and Center of Mass. The Experiment: In this experiment, you balance a meter stick, to...

    Torques and Center of Mass. The Experiment: In this experiment, you balance a meter stick, to balance the meter stick, attach masses at positions until the system is in equilibrium. The meter stick acts as if all its mass was concentrated at its center of mass. With the fulcrum at the center of mass, r (the distance from the axis of rotation to the place where the force is applied) is 0, so there’s no torque due to the meter...

  • A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum....

    A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum. When a 55.0-grammas is attached at the 14.0-cm mark the fulcrum must be moved to the 39.2- mark for balance. What is the mass of the meter stick Need Help? Raad is free to rotate an a ctions , verticale. A constant tangential force of 270 N applied to its edge causes the A large grinding wheel in the shape of a solid cylinder...

  • A fulcrum is placed at the 40 cm mark on a 50 g meter stick (center...

    A fulcrum is placed at the 40 cm mark on a 50 g meter stick (center of mass at the 50 cm mark). A 35 g mass is placed at the 10 cm mark. What mass would have to be placed at the 75 cm mark to balance the meter stick?

  • A meter-stick is bolted to a wall. The bolt (pivot) is at the 5 cm mark....

    A meter-stick is bolted to a wall. The bolt (pivot) is at the 5 cm mark. Someone pulls on the 75 cm mark with a 108 N force as indicated in the drawing. Find the torque . Give magnitude and direction. 11. A meter-stick is bolted to a wall. The bolt (pivot) is at the 5 cm mark. Someone pulls on the 75 cm mark with a 108 N force as indicated in the drawing. Find the torque. Make sure...

  • A54.0 meter stick is balanced at its midpoint (50.0 cm, zero point is a left end...

    A54.0 meter stick is balanced at its midpoint (50.0 cm, zero point is a left end of stick). Then 2500 welt hung with a light string from the 1967.0 cm point, and a 125 g weight is hung from the 16,0 cm point the figure below). Calculate the clockwise and counterclockwise torques acting on the board due to the four forces shown about the following axes: 50 cm 1) Calculate the clockwise torque if the axis is the 0 cm...

  • A slender uniform rod 100.00 cm long is used as a meter stick. Two parallel axes...

    A slender uniform rod 100.00 cm long is used as a meter stick. Two parallel axes that are perpendicular to the rod are considered. The first axis passes through the 50-cm mark and the second axis passes through the 11-cm mark. What is the ratio of the moment of inertia through the second axis to the moment of inertia through the first axis? Answer in two decimal places.

  • A uniform wooden meter stick has a mass of m = 799 g. A clamp can be attached to the measuring stick at any point Palong the stick so that the stuck can rotate freely about point P

    A uniform wooden meter stick has a mass of m = 799 g. A clamp can be attached to the measuring stick at any point Palong the stick so that the stuck can rotate freely about point P, which is at a distance d from the zero-end of the stick as shown. Part (a) Calculate the moment of inertia in kg-m of the meter stick if the pivot point P is at the 50-cm mark.  Part (b) Calculate the moment of inertia...

  • please show your work? Thanks Lecture Notes-pe A uniform meter stick may rotate about a horizontal...

    please show your work? Thanks Lecture Notes-pe A uniform meter stick may rotate about a horizontal anis of rotation through its 30 centimeter mark. Two point masses, each with the same mass as the meter stick, are attached to the meter stick at the 10 and 70 cm marks. The meter stick is displaced slightly from its vertical equlibrium position and oscillates through a small angle. Treat the meter stick like a uniform rod and find the period of this...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT