A meter-stick is bolted to a
wall. The bolt (pivot) is at the 5 cm mark. Someone pulls on the 75
cm mark with a 108 N force as indicated in the drawing. Find the
torque . Give magnitude and direction.
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A meter-stick is bolted to a
wall. The bolt (pivot) is at the 5 cm mark....
0/30 Torque and Conditions for Equilibrium. The pivot point of a meter stick is at 50.0...
0/30 Torque and Conditions for Equilibrium. The pivot point of a meter stick is at 50.0 cm. The first mass of 35.0 kg is placed at the 23.0 cm mark of the meterstick. What is the location of a mass - 65.0 kg that balances the meter stick (Sum of torques
A uniform meter stick is balanced with the pivot located at the 60 cm mark. And...
A uniform meter stick is balanced with the pivot located at the 60 cm mark. And a mass of 50 grams placed at the 85 cm mark. What is the mass of the meter stick?
A meter stick is found to balance at the 50.0 cm mark when placed on a...
A meter stick is found to balance at the 50.0 cm mark when placed on a fulcrum. When a 0.100 kg mass is attached at the 10.0 cm mark, the fulcrum must be move to the 34.0 cm mark for balance. a) What is the mass of the meter stick? b) How much torque does the 100 g mass exert on the meter stick around an axis at the new fulcrum (at 34.0 cm) c) How much torque does the...
Consider hanging masses off the ends of a meter stick which is nailed to the wall,...
Consider hanging masses off the ends of a meter stick which is nailed to the wall, as shown the figure. Take the meter stick to be a 1.0 m long massless rod, the nail is d = 12 from the end as shown, and it is free to rotate about this point. If I put a mass m_1 = 5.0 kg onto the left of the meter stick, how much mass m_2 should I put onto the right end to...
The meterstick shown is 100 cm long. It is free to pivot around its center of...
The meterstick shown is 100 cm long. It is free to pivot around its center of gravity (CG), which is at the 50 cm mark. There is a 21.0 N block hanging from the 80 cm mark. Decide where each of the other blocks should be placed, one at a time, to balance out the 21.0 N block. 3 2 At what mark on the meter stick would you place a 16.0 N block to balance the 21.0 N block?...
A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum....
A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum. When a 55.0-grammas is attached at the 14.0-cm mark the fulcrum must be moved to the 39.2- mark for balance. What is the mass of the meter stick Need Help? Raad is free to rotate an a ctions , verticale. A constant tangential force of 270 N applied to its edge causes the A large grinding wheel in the shape of a solid cylinder...
55) A 0.15-N meter stick is suspended from a spring scale at its 25-cm mark. When...
55) A 0.15-N meter stick is suspended from a spring scale at its 25-cm mark. When an object of unknown mass is hung from the meter stick on the 10-cm mark, the meter stick is in equilibrium. Draw an extended-body force diagram for the meter stick and (a) determine the mass of the object and (b) the reading on the spring scale.
One end of a meter stick is pinned to a table, so the stick can rotate...
One end of a meter stick is pinned to a table, so the stick can rotate freely in a plane parallel to the tabletop. Two forces, both parallel to the tabletop, are applied to the stick in such a way that the net torque is zero. The first force has a magnitude of 2.00 N and is applied perpendicular to the length of the stick at the free end. The second force has a magnitude of 6.00 N and acts...
A uniform meter stick of mass 1.5kg is attached to the wall by a frictionless hinge at one end. On the opposite end it i...
A uniform meter stick of mass 1.5kg is attached to the wall by a frictionless hinge at one end. On the opposite end it is supported by a vertical massless string such that the stick makes an angle of 40 degrees with the horizontal. Find the tension in the string and the magnitude and direction of the force exerted on the stick by the hinge.
the experimental part for this question is all answered there is only the last part where it says: Compute the net torque about 20 cm mark. Mass of the stick : 0.1383 kg Compu...
the experimental part for this question is all answered there is
only the last part where it says:
Compute the net torque about 20 cm
mark.
Mass of the stick : 0.1383 kg
Compute the net torque about the end of the stick.
please be sure to put detailed answer for both parts 1 and 2
thanks for the help!
Q1) Torques and equilibrium Part A: use the following methods to find the center of mass for a measuring stick...
0/30 Torque and Conditions for Equilibrium. The pivot point of a meter stick is at 50.0 cm. The first mass of 35.0 kg is placed at the 23.0 cm mark of the meterstick. What is the location of a mass - 65.0 kg that balances the meter stick (Sum of torques
Consider hanging masses off the ends of a meter stick which is nailed to the wall, as shown the figure. Take the meter stick to be a 1.0 m long massless rod, the nail is d = 12 from the end as shown, and it is free to rotate about this point. If I put a mass m_1 = 5.0 kg onto the left of the meter stick, how much mass m_2 should I put onto the right end to...
The meterstick shown is 100 cm long. It is free to pivot around its center of gravity (CG), which is at the 50 cm mark. There is a 21.0 N block hanging from the 80 cm mark. Decide where each of the other blocks should be placed, one at a time, to balance out the 21.0 N block. 3 2 At what mark on the meter stick would you place a 16.0 N block to balance the 21.0 N block?...
A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum. When a 55.0-grammas is attached at the 14.0-cm mark the fulcrum must be moved to the 39.2- mark for balance. What is the mass of the meter stick Need Help? Raad is free to rotate an a ctions , verticale. A constant tangential force of 270 N applied to its edge causes the A large grinding wheel in the shape of a solid cylinder...
One end of a meter stick is pinned to a table, so the stick can rotate freely in a plane parallel to the tabletop. Two forces, both parallel to the tabletop, are applied to the stick in such a way that the net torque is zero. The first force has a magnitude of 2.00 N and is applied perpendicular to the length of the stick at the free end. The second force has a magnitude of 6.00 N and acts...
the experimental part for this question is all answered there is
only the last part where it says:
Compute the net torque about 20 cm
mark.
Mass of the stick : 0.1383 kg
Compute the net torque about the end of the stick.
please be sure to put detailed answer for both parts 1 and 2
thanks for the help!
Q1) Torques and equilibrium Part A: use the following methods to find the center of mass for a measuring stick...
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