Question

Part A (Figure 1) shows a circuit with an area of 0.070 m2 containing a R=1.02 resistor and a C = 220 uF uncharged capacitor.

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Answer #1

induced emf in the loop, emf = A*dB/dt

= 0.07*(0.8 - 0.1)/(1*10^-2)

= 4.9 V

charge on the capacitor plates, Q = C*emf

= 220*10^-6*4.9

= 0.001078 C

= 1.1*10^-3 C

here induced current flows in counter clockwise direction.

so, upper plate should have positive charge

so, Q = 1.1*10^-3 C <<<<<<<------------Answer

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