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The copper shaft is subjected to the axial loads shown in (Figure 1). Figure < 1 of 1 Part A Determine the displacement of en

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FBD of section AB U 36 KN 7 A FAB Efx=0 :36-FAB=0 - FAB= 36 KN free Body Diagram for bar BC is 20-5KN 36 KN FBC A 225 B EN Ef

Efx=0 -36-225-225-9-9 + fcd = -0 i fen=27 KN Elongation of bar AB SAB = FAB. LAR AAB. E SAB - (36X103) (2000 mm) Tx (1972x 12

SBC = (9X103) X3750 TEX (29)ºx (262103) JBC -0.4678 mm for bar CD ded= FCO. LCD ACDE (27X103) x2500 IX(14)2 x 126x103 4 -SD =

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