Find the standard form of the equation of the parabola satisfying the given conditions. Vertex: (3, - 2); Focus: (3,-5) The standard form of the equation is 1. (Type an equation. Simplify your answer.)
Find the standard form of the equation for a parabola with focus at (3, -6) and directrix y = 4. The equation of the parabola in standard form is given by:
Find the standard form of the equation of the parabola with the given characteristic and vertex at the origin. Focus (20) Need Help? 11. [0/1 Points] DETAILS PREVIOUS ANSWERS LARCOLALG10 4.3.023 Find the standard form of the equation of the parabola with the given characteristic and vertex at the origin Directo y 2 = sy Need Help? Wach 12. [-/1 Points] DETAILS LARCOLALG10 4.3.025. Find the standard form of the equation of the parabola with the given characteristics and vertex...
Find the standard form of the equation of the parabola with vertex at the origin and fo
Find the standard equation of the parabola highlighted color brown. State all relevant info. corresponding to the parabola. (let : p=0.8) Find the standard equation of the parabola highlighted/colored in brown. State all relevant info. corresponding to the parabola. (let: p = 0.8) Round to nearest hundredths. THE FLASH Standard Equation of the Parabola is
Find an equation of a parabola satisfying the given information. Focus (8,0), directrix x= - 8 An equation for a parabola satisfying these conditions is (Type an equation. Simplify your answer.) .
Find the vertex, focus, and directrix of the parabola. Then graph the parabola.(x-4)2 = 12(y + 2) The vertex of the parabola is _______ (Type an ordered pair) The focus of the parabola is _______ (Type an ordered pair.) The directrix of the parabola is _______ (Type an equation. Simplify your answer.) Use the graphing tool to graph the parabola only.
Find the standard form of the equation of the parabola with the given characteristic(s) and vertex at the origin. y 10 Focus (-3.5, 0) -5 5 -51 -104
Find the standard form of the equation of the parabola with vertex at the origin and 3 focus at (0, -3). O A y = –6x² OB) y = 1x2 OC) y = 6x2 OD)x= -6y? DE) y = - 1/2 x ² OF) x = - 1 34² G) x = 1/3 4² O H) x = 6y²
10- Find the equation of the parabola described. Find the two points that define the latus rectum, and graph the equation. Vertex at (0,0); axis of symmetry the y-axis; containing the point (3,5) What is the equation of the parabola? 3- 6- 4- 2-1 X -10 -8 -6 -4 -2 2 4 6 8 10 (Use integers or fractions for any numbers in the equation.) Find the two points that define the latus rectum. The left point is and the...