Can you use gave a detailed instruction on
how to input in excel ?
For simplicity, let's assign t=0 to year 1999 and counting number of years after that. Then year 2000 corresponds to the value of t=1 and so on.
Put values for X, 't' and Y in different columns as shown -
X | Y | t |
2000 | 1362 | 1 |
2001 | 1778 | 2 |
2002 | 3031 | 3 |
2003 | 4001 | 4 |
2004 | 5010 | 5 |
2005 | 7092 | 6 |
2006 | 7934 | 7 |
2007 | 7863 | 8 |
2008 | 8038 | 9 |
2009 | 8708 | 10 |
2010 | 8675 | 11 |
2011 | 8994 | 12 |
2012 | 9325 | 13 |
Then we need to perform simple linear regression for dependent variable 'Y' and independent variable 't'.
For this, you need to use the 'Data Analysis' add-on from the 'Data' tab to access 'Regression' function as shown -
Then a prompt box will open up asking you to input the dependent variable and independent variable. Fill in the corresponding ranges by just selecting the cell region for each 'Y' and 't'. Also make sure to mark the 'Labels' option as we have labels in our first row. Your input should be similar to this -
Thats it. You should get the regression output as shown -
SUMMARY OUTPUT | ||||||
Regression Statistics | ||||||
Multiple R | 0.948612089 | |||||
R Square | 0.899864896 | |||||
Adjusted R Square | 0.890761705 | |||||
Standard Error | 949.6871213 | |||||
Observations | 13 | |||||
ANOVA | ||||||
df | SS | MS | F | Significance F | ||
Regression | 1 | 89154801.78 | 89154801.78 | 98.85158599 | 7.83196E-07 | |
Residual | 11 | 9920961.912 | 901905.6284 | |||
Total | 12 | 99075763.69 | ||||
Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | |
Intercept | 1393.846154 | 558.7469035 | 2.494593071 | 0.029791278 | 164.0525111 | 2623.639797 |
t | 699.9010989 | 70.39549297 | 9.942413489 | 7.83196E-07 | 544.9616635 | 854.8405343 |
Thus, we can use this output to solve the question as shown-
(a)
The estimate of standard error of estimate is: Standard error =
= 949.6871213
Thus, the estimate of
is:
Rounding upto nearest integer gives:
------------------------------------------------
(b)
The regression equation is written as -
Where
represents the rate of change of dependent variable 'Y' with
respect to the independent variable 't'.
From the output, we get the slope coefficient as: 699.9010989
So, LTWL size changes by 700 in average for a year.
------------------------------------------
(c)
For year 2016, t = 2016 - 1999 = 17
And the regression equation is -
So, for t = 17 we get the predicted value of Y as -
So, estimated number of patients in list = 13292
------------------------------------------------
(d)
For year 2011, t = 2011 - 1999 = 12
And the regression equation is -
So, for t = 12 we get the predicted value of Y as -
So, estimated number of patients in list = 9793
And as the actual number of patients in list in 2011 = 8994 (from data given)
So, error = e = 9793 - 8994 = 799.
____________________________________________
Note that, you would get the same result if you run the regression using 'X' directly as the independent variable. You can try doing it for practice if you want. Its a general habit of parametrizing time in years to smaller scale in order to reduce the variance of data.
Please ask if you have any doubt(s) in comment section.
Can you use gave a detailed instruction on how to input in excel ? Reserve Problems...
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