The height of a helicopter above ground is y = 3t². t is in
seconds and y meters. At t = 2s, a package is dropped from the
helicopter.
a-) How long does the package arrive on the ground? (g = 10 m /
s²)
b-) What is the speed when the packet reaches the ground? (Answer
with m / s)
y = 3t2
dy / dt = 6t
at t = 2 s,
y = 12 m
u = 12 m/s
so,
v = sqrt ( 122 + 2 * 10 * 12)
v = - 19.6 m/s ( answer to B - negative sign because velocity is downwards)
and
12 = 19.6 - 12 * t / 2
t = 3.15 seconds
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