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Let Z be a standard normal random variable. P(0.63<=Z<=c)=0.2515 Carry your intermediate computations to at least...

Let Z be a standard normal random variable.

P(0.63<=Z<=c)=0.2515

Carry your intermediate computations to at least four decimal places. Round your answer to two decimal places.

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Answer #1

solution i- Let z be a Standard Normal Randem Variable. given P10.63 s Zsc) = 0.2515 (C) - (0.63) = 0.2515 T T T 0.2515 0.735

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