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Q3. Green Airways flies several daily flights from Dallas to Chicago with 150-seat planes. Based on historical data, the flig

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Answer #1

First let us assume that the cost of the ticket is $ 100.

Now as it is given in the question the compensation cost or the cost of bumping the passenger is 10 times than the ticket price = 10*100 = 1000 $

Now let us calculate the cost of the airlines for each overbooking scenario :

Scenario 1 : Overbooked Seat = 0

No Shows Probablity Cost in $
0 0.01 0
1 0.1 100
2 0.63 200
3 0.26 300
Total Cost = (0*0.01) + (100*0.1) + (200*0.63) + ( 300*0.26) = 10 + 126 + 78 = 214

Scenario 2 : Overbooked Seat = 1

No Shows Probablity Cost in $
0 0.01 10*100 = 1000
1 0.1 0
2 0.63 100
3 0.26 200
Total Cost = (1000*0.01) + (0*0.1) + (100*0.63) + ( 200*0.26) = 52 + 63 + 10 = 125

Scenario 3 : Overbooked Seat = 2

No Shows Probablity Cost in $
0 0.01 2*10*100 = 2000
1 0.1 1000
2 0.63 0
3 0.26 100
Total Cost = (2000*0.01) + (1000*0.1) + (0*0.63) + ( 100*0.26) = 20 + 100 +26 = 146

Scenario 4 : Overbooked Seat = 3

No Shows Probablity Cost in $
0 0.01 3*10*100 = 3000
1 0.1 2000
2 0.63 1000
3 0.26 0
Total Cost = (3000*0.01) + (2000*0.1) + (1000*0.63) + ( 0*0.26) = 30 + 200 + 630 = 860

As we can see from the above scenarios :

The Seats Overbooked and the Total Cost incurred for the airline are :

Seats Overbooked Total Cost Incurred $
0 214
1 125
2 146
3 860

As we can see the total cost is the minimum at over-booked seats = 1 and then keeps on increasing , so in order to minimise the total cost the best case scenario for the airlines is to overbook = 1 seat.

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