Question

An AISI steel has a yield strength, Sy = 300 Mpa. Plot the failure locus and the load line in the attached diagram. Given that - Ох = 210 MPa, y = 160 MPa, and Txy = -45 MPa Hint: 04.0p -“70 +670 +1 + Ty

Answer 1

Given dato, Ir = 210 MPa Ty= 160 MPa Try 95 MPa. Sy= soompa find principal stress from the gioon expression JAI JA Ontry + On-by) ²+ eng? 2 TAI OD = 2lot 160 + 2 | (210-160)2+(-95) TAITA 185 t 5tos OA - 236.478 MPal TD= 133.52 MPa from maximum sheor Stress theory Zmax se by 2.fos

TA -00 s Sy 211 2 216.978 133.52 ooo 2x o 51.979 mpa < 150 mpa Soi the design is is safe plot th foieur locas. shown in the figure belowa JA Sy=100 mpa OBIOA 2 í 199.52,236.476 MPa a -Sy =-900 Мрс Sy= 200 MPa - sy=-300 mpa 97 is safe zone

According the distortion erorgd theory. JA 2002 - JANA < 2 Sy f.os 2 216.479?+ 121.52 21.6.978 X 131.52 2 < :) 42174.89 2 (2001 205.16 MPa s Joo MPa So, design is safe. plot foleure locus oy shown. TA 1 Sy=300 MPa Sy - 300 Mpa (OBICA) (123.521 206.478 Sy= 100 mpa TA MPa Sy= - 300 MPa it is in safe zone.

في وع draw both theory of diagram failun some shown the figure бA Joom pa А (DACA)- ( 113.52, 216.478 ) MPa -100MPa noompa A ajoo mpa Hence, 97 is clear thal the Stress volce is safe wir ti both theory of faieure. Heng, design is safe A