Question

3) Test the claim that seat belts and death are independent wearing Died survived (X=0.01) Wear Seat belt 10 50 Dont wear 20

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Answer #1

Here we have to check independence of two attributes therefore we use chi square test :

Let

A: Wear seat belt

B: death

Hypothesis is to be tested:

Но Attributes A and B are independent.

against

H_{1}:Attributes A and B are dependent.

Test Statistic:

\chi ^{2}_{1}=\frac{N(ad-bc)^{2}}{(a+b)(c+d)(a+c)(b+d)} this is chi square with degrees of freedom 1.

if number of rows(r)=2, and number of columns=2 then contingency table is,

A \ B B1 B2 Total
A1 a b a+b
A2 c d c+d
Total a+c b+d N=a+b+c+d

if we compare this contengency table to given table

A \B died(B1) survive(B2) Total
wear seat belt (A1) a=10 b=50 a+b=60
Dont wear seat belt(A1) c=20 d=30 c+d=50
Total a+c=30 b+d=80 N=110

therefore test statistic becomes:

\chi ^{2}_{1}=\frac{110*((10*30)-(50*20))^{2}}{(60)(50)(30)(80)}

\chi ^{2}_{1}=\frac{110*(300-1000)^{2}}{7200000}

\chi ^{2}_{1}=\frac{110*(-700)^{2}}{7200000}

\chi ^{2}_{1}=\frac{110*490000}{7200000}

\chi ^{2}_{1}=\frac{53900000}{7200000}

\chi ^{2}_{1}=7.4861............................................test statistic value.

critical value:

\chi ^{2}_{1},_\alpha = \chi ^{2}_{1},_{0.01} = 6.635

Decision Criteria:

if \chi ^{2}_{1}>\chi ^{2}_{1},_\alpha then reject Ho at \alpha % level of significance.

Here

\chi ^{2}_{1}=7.4861>   \chi ^{2}_{1},_\alpha = \chi ^{2}_{1},_{0.01} = 6.635   therefore we reject Ho at 1% level of significance.

that is we accept H1

means wearing seat belt and death are dependent on each other.

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