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Practice Problem 5 Part B What is the probability that Hank and Hazels male offspring will be a carrier of PFK deficiency? H


Purebred dogs weble to many genetic disorders. Cockerspanies in particulare prone to a disorder called canine phosphoruckas (
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Answer:

\rightarrowPart B:-

  • Given that cross is with Hazel and Hank.
  • PFK is a autosomal rcessive disorder.
  • Let P be the normal allele and 'p' be the mutant allele. it is said that Hazel is not a carrier of 'p' allele.
  • That means she is homozygous dominant (PP).
  • The genotype or information regarding the Haze is not provided in the question, so there is a possibility for him to be PP / Pp / pp.

Case 1 -

parents-- genotype -- PP (Hazel) x PP (Hank)

gametes-- P P

cross -- PP - all PP as no 'p' allele, so % of carriers = 0

Case 2 -

parents-- genotype-- PP (Hazel) x Pp(Hank)

gametes-- P P, p

cross--

P
P PP - normal
p Pp - carrier

Hence % of carriers = 50%

Case 3 -

parents-- genotype-- PP(Hazel) x pp (Hank)

gametes-- P p

cross-- Pp - 100% carriers.

\rightarrowPart C:

  • We know that Hazel is PP. and it is asked in the question that what is the probability that their unaffected girl child is a carrier.
  • To be unaffected there are two possible genotypes - either two be PP or Pp.

So, chance of girl child to be carrier = chance of Pp / total chances possible = 1/2

= 50%

Please ratae my answer.................................. thank u.........................

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