Question

Acetic anhydride is a clear liquid with a pungent, penetrating, vinegar-like odor. The largest application of acetic anhydride is as a raw material in manufacturing cellulose acetate fibers and plastics. It is also used in the production of aspirin, acetaminophen and other pharmaceuticals manufacturing. In an intermediate step in the production of acetic anhydride, carbon monoxide and carbon dioxide are reacted with hydrogen to make methanol according to the following balanced chemical equations: CO + 2H2 CH3OH CO2 + 3H2 - CH2OH + H20 A reactor feed stream containing 0.78 mol% of CO and 0.22 mol% of CO2 at a rate of 50 kg/h is reacted with a stream of H2. The H, enters the reactor at a rate of 26 m/h at 100 °C and 350 kPa. In the reactor, the conversion of CO is 60 % and the conversion of CO2 is 50 %. (a) Construct a flowchart and label the streams for the process described. [4 marks) (b) Determine the molar flow rates (mol/h) for all process streams and the mole fraction of each component in the product stream. [19 marks] (C) Now, we have a choice of either a pure CO feed or a pure CO2 feed fed into the reactor with the same mass flow rate instead of the mixture containing both CO and CO2, which one will produce more CH3OH? Evaluate and justify your answer. [3 marks]

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Answer 1

mal 0.76%. Co +0.22 malet. Com Cot Cor 50 kg/ CH₂Oh Reactor H₂O Hy 2604 / 0.22 (mo)co in fecel malt of Co₂ = 0.76 (mo) con = 44 le/pood malo of Coa 28 kg/kinal mw of minture 4480.78 + 2880.22 = 40.48 kg/kanal mass flow rate of minture = 50 kg/har. Molar flow rate of minture = solegler 40.48 kg/renal = 28 1235.2 molle mother Hy at 100k, and 380 kPa, Assume the rele behave like an Ideal gas time Pv=nRT Basic- l hy of n 350 kPa x 26m3 8.314 Imodiky 393k n=3508163 x26 = 2934.42 moles 8.3147 373 Basic - Time is taken as moles of minture in feed = 1235.2 mal moles of Cop in fecel 2008 0.22x123512 2470 = 271.74 mol moles of Co in feed=0.78*1235.2 963.45

= 963.45X016 = 578,07 mal = 135.87 mal 385.36 mol moles of H₂ Urrested. Co + 2H₂ no=963.45 → CH₂OH Conversion 60% Co₂ of 3H₂ CH₂OH + H₂O Co,= 271124 ChooH formed from Co Conversion Chych formed from Cas Conversion the formed = 135.87 mal - 271674XO'S moles of Co Remaining unrented I 014 963045 - = 963.45-578107 = moles of Cos Remaining unreacted total moles of Hy Consumed = 2x578.07 + 3x135.87 - 1563.75 = 2934.4-1563.75 = 137o. 67 mal total moles of Chizoh formed=57807 +135.87 © So In Prochect for Ihr of time = 713.94 mal flow rate of Co2 = 135.87 mallho Flowrate of Co 365.38 mallar filow rate of Chogoh = 713-94 malsos flow rate of H2O = 135.87 maller Flow rate of the 1370 67 maller 135.87 = 271.24-135.875

It's given that Conversion of Co is more into & Chizoh im Comparison with Coq emel Both Conversion Produced some amount of chyot by Consumption of imal of Co or imal of Com. Co in feed So place will produce more CH₂OH, Thank you