Standard solutions of calcium ion used to test for water hardness are prepared by dissolving pure calcium carbonate, CaCO3, in dilute hydrochloric acid. A 1.212 g sample of CaCO3 is placed in a 200.0 mL volumetric flask and dissolved in HCI. Then the solution is diluted to the calibration mark of the volumetric flask. Calculate the resulting molarity of calcium ion.
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Standard solutions of calcium ion used to test for water hardness are prepared by dissolving pure...
Standard solutions of calcium ion used to test for water hardness are prepared by dissolving pure calcium carbonate, CaCO3, in dilute hydrochloric acid. A 1.579 g sample of CaCO3 is placed in a 150.0 mL volumetric flask and dissolved in HCl. Then the solution is diluted to the calibration mark of the volumetric flask. Calculate the resulting molarity of calcium ion. Molarity M For convenience, one form of sodium hydroxide that is sold commercially is the saturated solution. This solution...
A standard iron solution was prepared by dissolving 0.0100 g of pure iron in acid then transferring to a 50.00 mL volumetric flask with orthophenanthroline as a complexing agent. At a wavelength of 540 nm, the absorbance of the standard was 0.239 in a 1.00 cm cuvette. A 0.149 g sample of an iron ore was crushed and digested in 5 mL of concentrated acid. The digested sample was then transferred to a 10.00 mL volumetric flask and diluted to...
A stock solution was prepared by dissolving 0.593 g of pure ASA (molar mass = 180.2 g/mol) with NaOH solution and diluting with water in a 1000 mL volumetric flask. This was followed by pipetting 4.00 mL of the stock solution into flask A and 5.0 mL of the stock into flask B. Flasks A and B were each diluted to 20 mL mark of the volumetric flask. What are the concentrations, in molarity, of ASA in flasks A and...
(10 pts) A solution is prepared by dissolving 1.239 grams of hydrochloric acid, HCI, in enough water to make 250.0 mL of solution. A 25.00 mL sample of this solution is diluted with water to a final volume of 100.0 mL. Now, you take 10.00 mL of that solution and dilute it to 100.00 mL What is the molarity of the final solution? (HCI 36.45 g/mol)
Determine the molarity of a solution of potassium chloride that is prepared by dissolving 1.4753 g of KCl in a 100-mL volumetric flask and filling it to the calibration mark with deionized water. Use a molar mass with at least 4 significant figures so that the number of SF in the calculated molarity is not limited. Show all calculations (including labeled conversion factors) and express the answer with the appropriate number of significant figures. According to the manufacturer, the volume...
8. A solution is made by dissolving 12.3 grams of calcium nitrate in enough water to form 500.0 mL of solution. sve (a) Calculate the molarity (M) of the resulting solution. (4) (b) What is the molarity of the nitrate ion, [NO3-), for the solution? (1) 9. What volume of 6.0 M HCl would need to be diluted with water to form 125 mL of 0.50 M HCI? (2) mivi
A stock solution was prepared by dissolving 0.593 g of pure ASA (molar mass = 180.2 g/mol) with NaOH solution and diluting with water in a 1000 mL volumetric flask. This was followed by pipetting 4.00 mL of the stock solution into flask A and 5.0 mL of the stock into flask B. Flasks A and B were each diluted to 20 mL mark of the volumetric flask. What are the concentrations, in molarity, of ASA in flasks A and...
A solution of sodium was prepared by dissolving 0.0309 g of NaCl in distilled deionized water and brought up to the mark in a 200 mL volumetric flask. 10.0 mL of this solution was diluted to 250.0 mL. What is the concentration (ppm) of sodium the final solution
b) In this experiment an aspirin tablet mark with deionized water. Using a pipette into a 100-mL volumetric flask and diluted to t make a 'diluted aspirin solution'. an aspirin tablet was placed in a 250-ml volumetric flask o dissolved in 10 mL of 1.0M NaOH solution, the flask was then 1.0M NaOH solution, the flask was then filled to the nized water. Using a pipette, 5.0 mL of this solution was added mL volumetric flask and diluted to the...
The formate ion, (CHO2-), is related to the acetate ion and forms ionic salts with many metal ions. Assume that 11.874 g of M(CHO2)2 (where M represents the atomic symbol for a particular metal) are dissolved in water. When a solution of 0.300 M sodium sulfate is added, a white precipitate forms. The sodium sulfate solution is added until no more precipitate forms, then a few excess milliliters are added. The precipitate is filtered, washed, and dried. It has a...