Question

QUESTION 2 a. Factorize completely 16x4 y²m-32 mx²b (1 mark) b. Using a scale 2 cm to represent 1 unit on the x axis and 1 cm to represent 1 unit on the axis, draw the graph of the function f(x)=x2-2x-3 for the domain-2<x54 marks) (6 c. From the graph above determine 1. II. The coordinates of the maximum or minimum point The roots of f(x)=x² – 2x-3 (3 marks) By explanation or otherwise on the graph how do you know that the graph is a function III.

Answer 1

a) To fachorise; 16xYm - 32m2o = 162 m ( xy -26) = 16 x'm{(24)*-(76)} = 162 n {xy +476) (xy-5b) b) PCt) = x=2x-3 meet y=f(2) -4 yax?-z2+=4 gth = (x-172 B-D=7+4) represents a parkola is at (1) whose veretex x у -4 o 3 0 y=2-22-3 dy 27-2 do if duy = 0 thea Xal 220 soat 2:1 thy is menimism

y 31-94-39 co (1-1) the f(1) w minimum II. 2-2X-3 20 - 3212-30 (x-3)&211) = 0 '. The 100ts ance 3,-/ IU. For every point of X there is a and for x=al and x = 3 the valle value lo remains samelia Y -o so is a many.one funct a) As per the given question let the So (8+26= 54 sit= 5% = 9 x 2.9-8=1 x = 1 b) the ileocecheon point 2+2y: 9 and 29-4-2 represents the point of contact 2 cars, 2004y = - => 42-Y -4 Adding x+2y +41 -- 24:9-4 SX"=5 XEI 9.4 Mb be 26 of of "yaa point of Condact n.

m 8,1 3-9, b = 2 (8)2-(-8) - 9 648 =-8 -9