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3) Determine the tension in each segment of the cable shown below. A E Чр B 15m р В. C Чкм བཅར་ SKU 18КМ Lam 1-3mt -am --3--

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Azy TAB Ey Ex D . 9k 5км i&KN -ОТ И (+z Me=0 2 Чx 3 410x 12 + 5X) 5- Tap Ən, - 95 - Tap 30 Х15 — 0 1947 30 3 – О 11 TAn 90 -— 15 + Tep (30 - 590 9+9 Tar - —15 Jч+ (30-50 the value in eoncl) put до 3 - 179р. -15 Jч+2° — г ) 9-9 2 Кs - Og 30 3 + 55 90Joint B TAB & E Fn -o T TBC. TBC 3 Tony 1 (3)2+(157014212 5 KN TAB 100)2 +167121427 0.3595 TBC - 18.5x0.267 = 0 |TBC = 13.747= 0 15-4D) Ted 5:172 181+(15-Y))2 from ean (3) (15-yo) (905427 51172 = 0 3 g YD=5.582 m put on egn (3) 9 TCD 51172 zo 81+(15-

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