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Question 11 (Mandatory) (1 point) A random sample of 150 mortgages in the state of Mississippi...
The internal auditing staff of a lical company performs a sample audit each quarter to estimate...
The internal auditing staff of a lical company performs a sample audit each quarter to estimate the proportion of accounts that are delinquent (more than 90 days overdue). For this quarter the auditing staff randomly selected 400 customer accounts and found that 80 of these accounts were delinquent. What is the 95% confidence interval for the proportion of all delinquent customer accounts at this company.
Question 9 20 pts Assume that a sample is used to estimate a population proportion p....
Question 9 20 pts Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places. 95% confidence; n = 396 x = 48 Question 10 20 pts Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Of 150 adults selected randomly from one town, 30...
A random sample of elementary school children in New York state is to be selected to...
A random sample of elementary school children in New York state is to be selected to estimate the proportion ?p who have received a medical examination during the past year. An interval estimate of the proportion p with a margin of error of 0.035 and 99% confidence is required. (a) Assuming no prior information about p^ is available, approximately how large of a sample size is needed? n= b) If a planning study indicates that p^ is around 0.70.7, approximately how large...
11. A simple random sample of size n is drawn. The sample mean, X, is found...
11. A simple random sample of size n is drawn. The sample mean, X, is found to be 17.9, and the sample standard deviation, s, is found to be 4.5. Click the icon to view the table of areas under the t-distribution. (a) Construct a 95% confidence interval about if the sample size, n, is 34. Lower bound: : Upper bound: (Use ascending order. Round to two decimal places as needed.) (b) Construct a 95% confidence interval about if the...
estion 3 of 5 > Atten Suppose that a simple random sample of size 400 selected...
estion 3 of 5 > Atten Suppose that a simple random sample of size 400 selected from a population, p, has 257 successes. Calculate the has 257 successes. Calculate the margin of error for a 90% confidence interval for the proportion of successes for the population, p. Show the results from each intermediate step performed to calculate the margin of error. First., proportion, , and use the sample proportion to calculate the standard error estimate, SE. Then determine the critical...
ILL UPVOTE 100%!!!!!! Potato Bruises A sample of 150 potatos were spot checked for bruises. "Yes"...
ILL UPVOTE 100%!!!!!!
Potato Bruises
A sample of 150 potatos were spot checked for
bruises. "Yes" indicates that there were visible bruises.
Yes
To determine the total number of "Yes" answers, use
=countif(select data in column A, "Yes")
Yes
To determine the total number of "No" answers, use
=countif(select data in column A, "No")
Yes
Yes
x--the number of bruised potatos
Yes
n--sample size (total number of potatos checked)
Yes
point estimate (pbar)--x/n
Yes
z--use = - norm.s.inv((1-confidence level)/2)
Yes...
A simple random sample of size n is drawn. The sample mean, x, is found to...
A simple random sample of size n is drawn. The sample mean, x, is found to be 19.4, and the sample standard deviation, s, is found to be 4.9. Click the icon to view the table of areas under the t-distribution. (a) Construct a 95% confidence interval about if the sample size, n, is 35. Lower bound: :Upper bound: (Use ascending order. Round to two decimal places as needed.) (b) Construct a 95% confidence interval about if the sample size,...
A simple random sample of size n is drawn from a population that is normally distributed....
A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, X, is found to be 110, and the sample standard deviation, s, is found to be 10 (a) Construct an 80% confidence interval about p if the sample size, n, is 14 (b) Construct an 80% confidence interval about if the sample size, n, is 18. (c) Construct a 98% confidence interval about if the sample size, n, is 14. (d)...
A report states that many hospital administrators are leery of the push toward mandatory reporting of...
A report states that many hospital administrators are leery of the push toward mandatory reporting of medical errors". Specifically, in a survey conducted between 2002 and 2003, a certain proportion of chief executives and operating officers in various states said that a state-run, mandatory, non-confidential reporting system would encourage lawsuits, despite evidence that patients are less likely to sue if doctors admit their mistakes and apologize. Based on the observed sample proportion, a 95% confidence interval for the proportion of...
1. A random sample of n measurements was selected from a population with standard deviation σ=13.6...
1. A random sample of n measurements was selected from a population with standard deviation σ=13.6 and unknown mean μ. Calculate a 90 % confidence interval for μ for each of the following situations: (a) n=45, x¯¯¯=89.8 ≤μ≤ (b) n=70, x¯¯¯=89.8 ≤μ≤ (c) n=100, x¯¯¯=89.8 ≤μ≤ (d) In general, we can say that for the same confidence level, increasing the sample size the margin of error (width) of the confidence interval. (Enter: ''DECREASES'', ''DOES NOT CHANGE'' or ''INCREASES'', without the...
Question 9 20 pts Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places. 95% confidence; n = 396 x = 48 Question 10 20 pts Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Of 150 adults selected randomly from one town, 30...
11. A simple random sample of size n is drawn. The sample mean, X, is found to be 17.9, and the sample standard deviation, s, is found to be 4.5. Click the icon to view the table of areas under the t-distribution. (a) Construct a 95% confidence interval about if the sample size, n, is 34. Lower bound: : Upper bound: (Use ascending order. Round to two decimal places as needed.) (b) Construct a 95% confidence interval about if the...
estion 3 of 5 > Atten Suppose that a simple random sample of size 400 selected from a population, p, has 257 successes. Calculate the has 257 successes. Calculate the margin of error for a 90% confidence interval for the proportion of successes for the population, p. Show the results from each intermediate step performed to calculate the margin of error. First., proportion, , and use the sample proportion to calculate the standard error estimate, SE. Then determine the critical...
ILL UPVOTE 100%!!!!!!
Potato Bruises
A sample of 150 potatos were spot checked for
bruises. "Yes" indicates that there were visible bruises.
Yes
To determine the total number of "Yes" answers, use
=countif(select data in column A, "Yes")
Yes
To determine the total number of "No" answers, use
=countif(select data in column A, "No")
Yes
Yes
x--the number of bruised potatos
Yes
n--sample size (total number of potatos checked)
Yes
point estimate (pbar)--x/n
Yes
z--use = - norm.s.inv((1-confidence level)/2)
Yes...
A simple random sample of size n is drawn. The sample mean, x, is found to be 19.4, and the sample standard deviation, s, is found to be 4.9. Click the icon to view the table of areas under the t-distribution. (a) Construct a 95% confidence interval about if the sample size, n, is 35. Lower bound: :Upper bound: (Use ascending order. Round to two decimal places as needed.) (b) Construct a 95% confidence interval about if the sample size,...
A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, X, is found to be 110, and the sample standard deviation, s, is found to be 10 (a) Construct an 80% confidence interval about p if the sample size, n, is 14 (b) Construct an 80% confidence interval about if the sample size, n, is 18. (c) Construct a 98% confidence interval about if the sample size, n, is 14. (d)...
A report states that many hospital administrators are leery of the push toward mandatory reporting of medical errors". Specifically, in a survey conducted between 2002 and 2003, a certain proportion of chief executives and operating officers in various states said that a state-run, mandatory, non-confidential reporting system would encourage lawsuits, despite evidence that patients are less likely to sue if doctors admit their mistakes and apologize. Based on the observed sample proportion, a 95% confidence interval for the proportion of...
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