Question

Please answer this question in detail using derivations and words.

mgsind = mu V. Given this, show how angular frequency depends on both the length of the string and the free-fall acceleration constant due to gravity. Noli. 0=am limesin) =

Answer 1

Answer:- Given, mgsine - ma on Angular frequency depends both length of string and free-fall acceleration constant (g) This is a call of simple penderlum Lluch face T ngcase masino T = mg Here, T=Tension in string ing caso (balanced) so, only ungling is relponsible for motion of boob in oscillatory motion. mgsing = me ma] Simple harmonie motion is accelerated motion. An ideal simple pendulum consists of a point mass 'm' suspended from a support by a mareless string of length 'L'. The equilibrium position of the mass is a distance I below the support of mass is displaced from its equilibrium position while keeping the string taut it enhebits periodic motion. when string makes an angle o with verticle, then the displacement of the mats from its equilibrium position the circular arc on the bob, are gravity and tension . along is s=20. Force, acting sy md² df2 do ing sino -gh sino sol of this eqn df

2 oct) = 8 man ablut +O) with wa w = g/l Time period, T- 27/w for uscillation T= 20 Jeg