Question

please kindly make solution and answers visible. thanks

Each sweat shop worker at a computer factory can put together 4.8 computers per hour on average with a standard deviation of 0.9 computers. 18 workers are randomly selected to work the next shift at the factory. Round all answers to 4 decimal places where possible and assume a normal distribution a. What is the distribution of X? X-N b. What is the distribution of a? ä - N/ c. What is the distribution of *? -N d. If one randomly selected worker is observed, find the probability that this worker will put together between 4.7 and 4.8 computers per hour. e. For the 18 workers, find the probability that their average number of computers put together per hour is between 4.7 and 4.8. f. Find the probability that a 18 person shift will put together between 88.2 and 91.8 computers per hour. 1 g. For parte) and f), is the assumption of normal necessary? Yes No h. A sticker that says "Great Dedication" will be given to the groups of 18 workers who have the top 15% productivity. What is the least total number of computers produced by a group that receives a sticker? minutes (round to the nearest computer)

Answer 1

= 0.1813 Andy 0.1813 To find P[ 88-2 CEx <91.8 =P[ x 88-2-86.4 3-8184 3x - 86.4 3.8184 91.8 - 86.4 3.8184 = P [ 0.4714LZ<1.4142] = $(1.4142) - $ (0.4714) 0.24 003, fy Amy 0.2 400 g) Yes. E since schee na 18 is not we cannot use CLT large sample Let; be required of computers To find a so that; -0.13 P[Ex>x =) P EX 2 x] = - or 85 1 Lx-86.4 I 0.85 EX-86.4 3.818 4 >> PE - $ 0.8184 3.8184 X-86.4 3.8184 = 0.855$ (1.0364) ( In Noom)

- 86.4 => = 1.0364 3.818 4 => x = 86.4 +(1.0364 x 3-8184) = 90.3574. ^ 91 Any al computers.