ANSWER:
Given that,
Evaluate the combination. 10C3
We know that,
C(n,r) = nCr = n! / (r!(n-r)!)
10C3 = 10! / (3!(10-3)!)
10C3 = 10! / (3!*7!)
10C3 = (10*9*8*7*6*5*4*3*2*1) / ((3*2*1)*(7*6*5*4*3*2*1))
10C3 = 3628800 / ((6)*(5040))
10C3 = 3628800 / 30240
10C3 = 120
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