Question

A container contains 35 green tokens, 5 blue tokens, and 4 red tokens

A container contains 35 green tokens, 5 blue tokens, and 4 red tokens. Two tokens are randomly selected without replacement Compute P(FIE). 


E - you select a non-red token first 

F - the second token is red

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Answer #1

according to given question we have to find conditional probability of token is red given that first selected token is non red.

4 tokens are red and 40 tokens are non red

p(F) = 4/43 , because after selecting 1st token there are only 43 token left.

p(E) = 40/44

now conditional probability from Baye's theorem can be find out as follows

p( E\cap F ) /p(E)

4/43

0.093

please like ??

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