Solution :
Given that ,
n = 20
Total degrees of freedom = 20 - 1 = 19
Test statistics = SSTR / 3 / SSE / 16
= 6750 / 3 / 8000 / 16
= 4.5
D)
VW 03 DOLL SSTR =6750 SSE = 8000 nt=20 HouM,=M2 = M3=M4 Hai at least one...
SSTR = 6750 SSE = 8000 nt= 20 Ho: u1=u2=u3=u4 Ha: at least one mean is different The test statistic to test the null hypothesis equals: 4.5 0.84 0.22 4.22
SSTR= 6750 SSE = 8000 nt = 20Ho: u1=u2=u3=u4 Ha: at least one mean is differnt At alpha=.05 the null hypothesis A. was designed incorrectly B. None of these C. Should be rejected D. Should not be rejected
D Question 18 SSTR-6.750 SSE - 4,000 n - 20 Ha Ha gult gulla at least one mean is different H The test statistic to test the null hypothesis equals: 0.22 0.84 6.00 4.5 1 pts D Question 19
Please answer this question based on the following data. SSTR = 6,750 H0: μ1= μ2=μ3=μ4 SSE = 8,000 Ha: at least one mean is different Nτ = 20 The null hypothesis is to be tested at the 5% level of significance. The p-value is less than .01 between .01 and .025 between .025 and .05 between .05 and .10
While conducting a one-way ANOVA comparing 6 treatments with 10 observations per treatment, the computed value for SS(Treatment)= 1, and SS(Error)=24. Calculate the value of F. Round off the answer to 2 decimal digits A study was conducted to determine the association between the maximum distance at which a highway sign can be read ( in feet) and the age of the driver ( in years). Fourty drivers of various ages were studied. The summary statistics for distance and age are...