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D Question 18 SSTR-6.750 SSE - 4,000 n - 20 Ha Ha gult gulla at least one mean is different H The test statistic to test the
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Answer #1

Here test statistic is given by F distribution as

MSTR F Fdfastrdf MSE

where

MSTR = SSTR/(4-1) (Because there are 4 tretaments in the given question)

MSE = SSE/(nt - 4)

SSTR/3 SSE/20 - 4) 6750/3 - = 2250/375 = 6 6000/16 =

So the F statistic is 6 which will follow F distribution with 3, 16 df.

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