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Please answer this question based on the following data. SSTR = 6,750    H0: μ1= μ2=μ3=μ4 SSE =...

Please answer this question based on the following data.

SSTR = 6,750    H0: μ1= μ2=μ3=μ4
SSE = 8,000    Ha: at least one mean is different
Nτ = 20

The null hypothesis is to be tested at the 5% level of significance. The p-value is    

less than .01

between .01 and .025

between .025 and .05

between .05 and .10
math   Statistics-And-Probability   
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Answer #1

Solution :

Given that ,

SSTR = 6,750   
SSE = 8,000   
Nτ = 20

df1 = 3

df2 = 16

F = (6750 / 3) / (8000 / 16) = 4.5

P-value = 0.01767

The null hypothesis is to be tested at the 5% level of significance.

The p-value is  between .01 and .025

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