Question

Styles 6. Insert a picture of your pedigree chart for this family with genotypes filled in here. 7. Which pattern of inheritance do you think the disease shows? Explain your reasoning. 8. Patient 1 and Patient 2 in the pedigree chart would like to know what the chances are that they will have a child with the disease. What do you tell them? Use a Punnett Square to show your work. Using Punnett Squares for human conditions and diseases The patterns of inheritance for many diseases are already known by scientists. In that case, genetic counselor collects a lot less information from a family in order to help them determine risk and outcomes in their children 9. Tay Sachs Disease is an autosomal recessive disease. That means that it is carried on one of the autosomal chromosomes and that only individuals with the two recessive disease alleles will have the disease phenotype. John and Sue are both carriers of the disease. Use the letters Tandt to represent alleles. a. What is John's genotype? Sue's genotype? b. What percentage of their children would you predict to have Tay-Sachs Disease? Show your work with a Punnett square

Answer 1

ANSWER

Part 6

Pattern of Puheritance & Aurosomat recessive T. aa Aa Aa aa Aa Aa Aa T. Aa аа aa ܘܘ Aa Aa аа aa Aa Aa a Aa aa TV. aa Aa Aa Aa Patient Aa Patient 2 Pedigree for parieur 2 Pedigree for patient I

Part 7

The above disease is displaying autosomal recessive pattern. In this, person carries both the mutant alleles and thus, gets affected with it. The disease is known to affect almost equal number of males and females in each generation. This feature is restricted to autosomal diseases however, in X-linked diseases, males are more likely to be affected while females serve as carriers. Another important point is that autosomal recessive traits or disease can skip a generation which does not happen in case of autosomal dominant diseases. We can observe in the left pedigree (belongs to patient 2), no one is affected in generation IV which includes patient 2 as well.

Part 8

Half (50%) of the children would be affected with disease from the mating between patient 1 and patient 2.

Patient I х Patient 2 오 аас X Aa Gameter A offspring A Aa aa caroler Affected usaffected or and 50% children would be affected 50% would be unaffected Carsiers. with the disease

Part 9

A. As it is already mentioned that both John and Sue are the carriers of Tay-Sachs disease. This means they are carrying one normal allele and one mutant allele. As a result, normal allele is efficient in suppressing the effect of mutant allele. Thus, both John and Sue are normal or unaffected. However, they are carriers of mutant allele and their genotypes are given below-

John's genotype- Tt

Sue's genotype- Tt

B. One out of four children (25%) would be affected with the disease.

John Sue TE TE Genotype Gametes Х 0 G T t Childrens q T ITT TE t Tt tt a 74 25 children would be affected with Tay-Bachs disease.