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Question 17 12 points A direct mapped cache holds 64KB of useful data (not including tag or control bits). Assuming that the
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Answer #1

Block Size = 32 byte => 2^5

Cache size = 64KB
Number of words = 2^16 / 2^5 => 2^11

Offset = 5
Index = 11
Tag = 32 - 5 - 11 => 16

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Thanks, let me now if there is any concern.


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