Question

(a) Plot the digital signal corresponding to the sequence "11010" with a transmission rate (RA) equals 1 Mbps using the following line codes: -On-Off (uni-polar) Non-Return-to-Zero (NRZ) with a rectangular pulse p(t) = A rect() -Polar Return-to-Zero (RZ) with a rectangular pulse p(t) = A rect 650) -AMI (Bipolar) (NRZ) with a rectangular pulse p(t) = A rect (b) Determine the null-based (zero-crossing) essential bandwidth and the average power for the line codes used above. (c) Determine the minimum bandwidth (for zero ISI) and the corresponding pulse shape p(t) and average power. (d) If M-ary (M=4) polar RZ communication system is used, determine the transmission rate (symbols/sec) and average power for the same noise margin of the polar binary).

Answer 1

e 14 0 @ Digital sequence '11010 given and tranemission rate (Ro) i Mbps. a on-off (unipolar) Non-return-to zuo (wrz) with rectangulai pulse P[]) =_A_rect ( #s) plot of Arect IPlt) a A suet ( I'To t- -Tol2 Tola 1 To To fig: ON-Off ( unipolar NRZ) ① Polar Return-to-zelo (R2) with Plt) = A rect Lt A rect 0.5 TD rectangular pulte To/ Plt) 9 +14) A Toll Toly Toly

t- - A Tol2 Tol2 fij: Polar (Return to zuse) AMI ( Bipolas ) NRZ Alternate Mark Inversion rectangular pulse_Plt) – Arectiu 1 Plt) AMI 2 with To Tь -TO2 To/2 t o t A in. fig: AMI (Bipolas) Nez. which for 'Y' altunate muk inversion is done fas low line is drawn and