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4. A top brand of a popular pickup trucks life is normally distributed with its mean, 12 years and standard deviation, 4 yea
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Answer #1

\mu = 12 years

\sigma = 4 years

1.2% = 0.012

(4)

when area =0.012

value of Z = - 2.257

let desirable warranty = x years

so we have

Z=\frac{x-\mu }{\sigma }

-2.257=\frac{x-12 }{4 } \Rightarrow x= 2.972

x= 2.972 years Answer

(5)

When x=2

Z=\frac{2-3.2 }{0.61 } = -1.9672

P( x > 2) = 1- area from left to (z=-1.9672)

= 1- 0.02458

= 0.97542 Answer

(6)

When n= 30

T = 3.5

Z=\frac{\bar{x}-\mu }{\sigma/\sqrt{n} }

Z=\frac{\bar{x}-\mu }{\sigma/\sqrt{n} }=\frac{3.5-3.2}{4/\sqrt{30}} =0.41079

P(T <  3.5) = area from left to( Z= 0.41079)

= 0.6594 Answer

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