Question

Two small-sized objects are placed on a uniform 9.00 kg plastic beam 3.00 m long, as shown in (Figure 1). Assume that mi = 3.25 kg and m2 = 7.60 kg Part A 0 at the left end of the beam. Find the location of the center of mass of this system by setting I Express your answer in meters. Templates Symbols Undo resilo Pese keyboard shortcuts help Tam In from the left-hand end of the beam Submit Request Answer Part B Find the location of the center of mass of this system by setting I = 0 at the right end of the beam. Express your answer in meters. Templates Symbols undo regio keyboard shortcuts help m from the right-hand end of the beam Figure < 1 of 1 Submit Request Answer 9.00 ks 60.0 cm 3.00 m Part C Do you get the same result both ways?

Answer 1

If the origin is at the left end then the location of the center of mass is, L mx + m2X2 +M (4) 2 x m, + m2 +M 3 (8.25)(0)+(7.60)(3-0.60)+(9) 2 8.25 +7.60+ 9 =1.30 m If the origin is at the right end then the location of the center of mass is, L m.x1 + m2x2+M 2 Y m; + m2 +M 3 (8.25)(-3.0) + (7.60)(-0.60) + (0) - 2 8.25 + 7.60+ 9 =-1.72 m