Two-Way ANOVA
Find the 3 F statistics for this two-way ANOVA, to look at the interaction between caffeine use and gender on memory scores in a list of 9 words. Use alpha .05 to test whether the null was correct or not.
A1 |
A2 |
A3 |
|
B1 |
5 |
4 |
4 |
2 |
6 |
9 |
|
1 |
3 |
7 |
|
4 |
1 |
5 |
|
2 |
3 |
4 |
|
B2 |
6 |
6 |
5 |
2 |
7 |
7 |
|
3 |
4 |
5 |
|
3 |
3 |
4 |
|
2 |
3 |
8 |
Please help!!
Using Excel. go to Data, select Data Analysis, choose Anova: Two-Factor With Replication. Put all values along with headers in input range at alpha = 0.05and rows per sample = 5.
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
B | 2.13 | 1 | 2.13 | 0.660 | 0.425 | 4.260 |
A | 40.27 | 2 | 20.13 | 6.227 | 0.007 | 3.403 |
Interaction | 1.87 | 2 | 0.93 | 0.289 | 0.752 | 3.403 |
Within | 77.60 | 24 | 3.23 | |||
Total | 121.87 | 29 |
F statistic (B1 and B2) = 0.660
F statistic (A1, A2 and A3) = 6.227
F (Interaction) = 0.289
Intercation effect
H0: There is no significant interaction between caffeine use and gender on memory scores in a list of 9 words
H1: There is a significant interaction between caffeine use and gender on memory scores in a list of 9 words
p-value = 0.752
Level of significance = 0.05
Since p-value is more than 0.05, we do not reject the null hypothesis.
So, there is no significant interaction between caffeine use and gender on memory scores in a list of 9 words.
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