Question

4. An ideal gas with constant specific heats undergoes a process from an initial pressure of 50 kPa and initial specific volume of 4 m^3/kg to a final pressure of 80 kPa and final specific volume of 5 m^3/kg. The mass of the carbon monoxide is 3 kg. The gas has a molar mass of 44 kg/kmol and a specific heat at constant volume of 0.98 kJ/(kg∙K). Determine the entropy change of the gas during the process in kJ/K.

Answer 1

Cp-Cv=R

Change in entropy of gas is 0.679 KJ/K

Ym3 /kg m= M = 4 4 kgmol, 7 Giveni P, = 50kPa , v. P2 = 80 kPa 5 m²/kg 3 kg Cu = 0.78 kJ / kg -k. Change in entropy, ds = max ln (12) + Cela / Ve do= C ln //2) + ( + R). In (V2 (l M CP - Cv = R/M R i Universal Gas Constant R = 8.314 J/molk do= 0.98 ln (80) + 10.98 +0.008314). In s 50 ЧЧ 4 ds=0.4606 t 0.2187 ds= 0.679 KJ /KL