Calculate current through individual resistors in the following circuit diagram
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Loop1:
-30+50i1+20(i1-i2)+80(i1-i4)=0
Loop2:
20(i2-i1)+30(i2-i3)+15(i2-i4)=0
Loop3:
12+20(i3-i5)+30(i3-i2)=0
Loop4:
-20+80(i4-i1)+15(i4-i2)=0
Loop5:
20+20(i5-i3)+60i5=0
From loop2 and loop4:
If we solve we get equation in terms of i3 ,i2 and i5.if we substitute in loop3 we get equation in terms of only i3 and i2,similarly solve loop 3 and loop 5 we get in terms of i1 and i4 ao fibally of we solve those equations we get answer.
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