Question

A compound has the H NMR spectrum shown below. Identify the compound. 11 10 9 00 7 6 UI 4 3 2 1 O None of these compounds fi

A compound has the H NMR spectrum shown below. Identify the compound. 3H triplet 2H triplet 2H 11 10 9 00 7 0) 5 4 3 N 1 0 N

A compound has the H NMR spectrum shown below. Identify the compound. 10 9 00 7 6 5 3 2 1 CH2Cl2 None of these compounds fit

A compound has the H NMR spectrum shown below. Identify the compound. 2H triplet Зн triplet 2H 11 10 9 8 7 6 5 4 3 2 1 он No


A compound has the H NMR spectrum shown below. Identify the compound. 2H triplet Зн triplet 2н 11 10 9 О. 7 6 - N 5 А. 4 ОН О


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Answer #1

first spectra from Top

Answer is

-CN

explanation: NMR has peak only in aromatic region in the given option only benzonitrile will have peak only in aromatic region whereas other option will have peak in aliphatic region also.

second spectra from top

Answer is

explantion: in aliphatic region two triplet and one mutiplet is due to n-propyl group and peak at aromatic region is due to phenyl group terefoe NMR spectra is belong n-propylbenzene

third spectra from top

Answer is CH3CN

explanation: the peak is slightly downfielded due to electron withdrawing nature of CN group. for benzene, CHCl3, CHCl2 will more downfielded singlet peak. for cyclohexane we will have upfielded singlet peak. therefore answer is CH3CN

fourth and fifth spectra from top

Answer is

ОН

explanation: the two triplet and one mutiplet is due n-propyl group. the triplet peak at 3.5 ppm is due to methylene group attached to oxygen

the singlet at around 2.1 ppm Is due to hydroxy group

therefore NMR belong to n-propanol

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