Question

Heading 2 Title Sut 18) The heating element in an iron has a resistance of 24 22. The iron is plugged into a 120 V outlet. a) What is the power dissipated by the iron? 19) Given a timing circuit, you are asked to connect the following components in series. A 4mH and a 200 22. They car connected with a 30 V voltage source that has angular frequency of 250 rad/s. e) What is the impedance of the entire circuit? 1) What is voltage across both the resistor and capacitor? D) Calculate the phase angle h) What quadrant would you find this angle? nina into the node (located under R), current

Answer 1

18) Given:

R = 24 ohm

V = 120 V

Power dissipated by the wire = [answer]

V2 R 1202 24 = 600W

19) Given:

R = 200 ohm

L = 4 mH = 0.004 H

$\omega = 250 rad/s$

Now, the inductive reactance is

XL = EL = 250 * 0.004 = lohm

e) The impedance of the circuit = $Z = \sqrt{R^{2}+X_{L}^{2}}=\sqrt{200^{2}+1^{2}}=200.0025ohm$ [answer]

f) The r.m.s current in the circuit is $i_{r.m.s}=\frac{V_{r.m.s}}{Z} =\frac{120}{200.0025}=0.599993A$

Therefore, the voltage across the resistor is [answer]

The voltage across the inductor is [answer]

g) The phase angle is the angle between the total voltage and voltage across the resistor.

Therefore, the phase angle is $\phi=tan^{-1}\frac{0.599993}{119.999} =0.29^{\circ}$ [answer]