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Your height as you dress in front of a spherical mirror in the morning for your 7:30 class is h. The absolute value of the fo

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20.329 m is uprite And focal length is negative (all Given height of object : focal length, $ = 38.9 em Image height of imageNow _magnificalim in terms of distance image & object distance u O: 1069 V egn u formula using mirror we calculate value ofv0.1069 41 - 0 10 69 XF0:389) 2 - uch) -le? t + 0.10694 + 0.4305 = 0 0.38944 0.1069 u +0.4305-0 By using sign conversion fort

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