Question

QUESTION 12 To improve the efficiency of an amplifier, you have to a reduce load power b. increase supply current OC. reduce supply voltage od decrease unwanted power losses QUESTION 13 If the output of a transistor amplifier is 5 V rms and the input is 100 mVrms the voltage gain is O as w 6.500 O c 50 d. 100

Answer 1

Q12: Answer: efficieny of an amplifier is defined as the ratio between output power to total power consumption. It means when power consumption or power losses is very less then efficiency will increase. [Hence option ② is correct] 013 solution : Given, output voltage = surms input voltage = 100 mv rms voltage gain is defined by output voltage input voltage voltage gain = Output voltage 5 CSX10 input voltage 10 X 103 50 voltage gain [Hence, option is correct 014 collector current IB Base current solution: If DC current of transistor = 30, Is = ima It means B Coc. Current goin): ICS For linear region, Ic = ß IB 30 x ima [Hence option is correct 30 mA

015 solution : we know that frequency is zero for a DC supply but supply but some frequening some frequenig is applied for AC supply, when we calculate value of capacitors at AC then its value is very small and it acts short circuit. Also we know capacitor block DC but it paises AC supply: Henu option (6) is is correct as