Question

tound to 3 decimal places as needed pls

This Question: 1 pt 18 of 24 16 completo) This Test: 24 pts possible Use the given data set to complete parts (a) through (c) below. (Us 0.05) x 10 B 13 9 7.47 6.78 12.75 7.11 11 781 14 BR) 6 6.08 & 539 7 12 8.15 574 Click here to view a table of critical values for the correlation coefficient a. Construct a scatterplot. Choose the correct graph below OD 16 4 Oc 4 OS Ay 16 12 @ 12 16 124 12 . 4 4- 4 12 b. Find the linear correlation coefficient, then determine whether there is sufficient evidence to support the aim of a new correlation between the two variables The Incar correlation coefficientia (Round to three decimal places as needed) Using the linear correlation coeficient found in the previous stop, dermine whether or is the evidence to support the aim of a near correlation between the two variables. Choose the correct anwww below Click to select your answers

Answer 1

(a) The ScatterPlot in option D is the correct one

(b)The linear correlation coefficient is r = 0.815

Corresponding to n = 11, r = 0.815 is highly significant

There is sufficient evidence to support the claim of a linear correlation between the two variables

(c) The ScatterPlot reveals a perfect straight line pattern, except for the presence of one outlier.

X Values 10,8,13,9 ,11,14,6, 4,12,7,5 Y Values 7.47,6.76 , 12.75,7. 11,7.81,8 .83,6.08, 5.39,8.15 ,6.42,5.7 4 Y Values X Values Y - My (Y - My)2 X - MX 1.000 -1.000 4.000 0.000 2.000 5.000 -3.000 -5.000 3.000 -2.000 -4.000 -0.031 -0.741 5.249 -0.391 0.309 1.329 -1.421 -2.111 0.649 -1.081 -1.761 (X - Mx)2 1.000 1.000 16.000 0.000 4.000 25.000 9.000 25.000 9.000 4.000 16.000 0.001 0.549 27.553 0.153 0.096 1.766 2.019 4.456 0.421 1.168 3.101 (X - Mx)(Y - My) -0.031 0.741 20.996 0.000 0.618 6.645 4.263 10.555 1.947 2.162 7.044 Mx: 9.000 My: 7.501 Sum: 110.000 Sum: 41.283 Sum: 54.940 Result Details & Calculation Key X Values = 99 Mean = 9 (X - Mx)2 = SSx = 110 X: X Values Y: Y Values My: Mean of X Values Mji Mean of Y Values X - MX & Y - Mji Deviation scores (X - MX)? & (Y - My)2: Deviation Squared (X-MX)(Y - My): Product of Deviation Scores Y Values = 82.51 Mean = 7.501 ECY - My)2 = SSy = 41.283 X and Y Combined N = 11 (X - MX)(Y - My) = 54.94 R Calculation r= (X - My)(Y - Mx))/ VI(SSx)(SSy)) r = 54.94 / ((110)(41.283)) = 0.8153 Meta Numerics (cross-check) r = 0.8153 The value of Ris 0.8153. This is a strong positive correlation, which means that high X variable scores go with high Y variable scores (and vice versa).