Question

Find the characteristic equation of A, the eigenvalues of A, and a basis for the eigenspace corresponding to each eigenvalue.
0 0
Add a comment Improve this question Transcribed image text
Answer #1

$(a). The characteristic equation is $\;|A-\lambda I|=0\;$\\ That is $\;(-5-\lambda)(1-\lambda)(3-\lambda)=0\;$\\ Therefore, the characteristic equation is $\;|A-\lambda I|=0\;$\\ That is $\;-\lambda^{3}-\lambda^{2} +17\lambda-15=0\;$\\ \\(b). Therefore,the eigen values are $\;\;-5\;,\;1\;,\;3\;.\;$\\ \\(c). If $\;\lambda_{j}\;$ is a given eigen value, then an eigen vector corresponding to $\;\lambda_{j}\;$ is a non-zero solution vector of the linear system$\;(A-\lambda_{j}I)X=\bar{0}\;$\\ Therefore, we get $\;u=(1,0,0)^{T}\;,\;v=(9,8,16)^{T}\;,\;w=(1,6,0)^{T}\;$ as eigen vectors corresponding to the eigen values $\;-5,\;1,\;3\:$ respectively.\\ Therefore, \\A basis for the eigen space of $\:\lambda_{1}=-5\:$ is $\;B_{1}=\{(1,0,0)^{T}\}\;$\\ A basis for the eigen space of $\:\lambda_{2}=1\;$ is $\;B_{2}=\{(9,8,16)^{T}\}\;$\\ A basis for the eigen space of $\:\lambda_{3}=3\;$ is $\;B_{3}=\{(1,6,0)^{T}\}\;$\\

Add a comment
Know the answer?
Add Answer to:
Find the characteristic equation of A, the eigenvalues of A, and a basis for the eigenspace...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT