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Resources Element 2 (pm) A crystal was analyzed using X-ray diffraction with radiation from a chromium source. The observed a
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Answer #1

wavelength of Chromium source, \lambda = 229 pm = 2.29 X 10-10 m

Angle \theta = 11.27o

Using Braggs equation, n\lambda = 2\: d\: \sin\theta

Taking n=1, i.e. primary interaction

\lambda = 2\: d\: \sin\theta

2.29\:X\:10^{-10} = 2\: d\: \sin(11.27)

d=\frac{2.29\:X\:10^{-10} }{2\: \sin(11.27)}= 5.8588\:X\:10^{-10} \; m = 585.88\; pm

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