Question

Column1 Column2 Column3 Small Ring Large Ring mass (8) 476 476 Inner Diameter (cm) 2.7 5.4 Outer Diameter (cm) 3.93 6.05 I Calculated | Measured % Error

From this data I am having a hard time finding Inertia Calculated, Inertia Total and I0.

In this case Inertia Calculated is 1/2 * M (R1^2 + R2^2) and Inertia Total is MgRp/alpha - MRp^2. Rp = 12.5 mm and M = 10 grams.

Answer 1

Ars:- mau lg) small bum Large Ring 7 19m) 476 476 Inney dea. 1cm) 2.7 5.4 outey dia(cm) 3.93 GOS calculated I "I I IM ( REP+R?) 2 Calented 'I + * 0.476 (67.75* x 10-4 + (3.931° x104)) Ix0.476 2 cox 12.7)2 + 13.9312) 사이 I, 5.4*10-4 kg. m2 ta * *0.476 [ 15.402 + 16.05)23.10-4 m 2 I. 15.65 x 10-4 kg. m mees tapedia mg Rp MRp2 Rp = 12.5mm lo gm.

Table-2 w/o Ring small king w/ laye 0.9019 0.776 0.6899 Aipha ocel. -1.020 G -0.9286 alpha Dee -1-2154 -0.26275 -0.05 935 -0.0763 alpha I I2 I I I, - lox 10-3 x 9.8 x 13.5*10-3 10x10-3x (12.50°x 10-6 0.26275 I 4.6*10-3 kg.H2 (negative sign Not Needel) Ia = 10x10 3x 'x 9.8 x 12.5x10 10 x 10-3 x(17.519x lor 0.05 935 Ia 0.020 kg. 12 Is lox 10-3x 9.8 x 12.54 10-3 - Joxlo-" x 11215) 2x 10-6 -0.6763 I3) 0.016 kegina