H2O(l) <===> H2O(s)
As we know that water loses heat and forms ice(that's why for formation of ice, we try to decrease the temperature of system so that maximum heat can be released.)
Heat is released when water changes from liquid to solid.
So, is negative.
Entropy(S) is denoted from randomness of particle.Greater the randomness,greater will be its entropy.
As particles in solid are more closely packed than liquid, so randomness in solid is lesser than that of liquid.
This shows that entropy of liquid is greater than that of solid,So is negative.
For the following example, identify the following. H2O(0) - H2O(s) O a negative AH and a...
For the following example, identify the following. H2O(l) + H2O(g) a negative AH and a positive AS a positive AH and a positive AS It is not possible to determine without more information. a positive AH and a negative AS O a negative AH and a negative AS
2. For the following example, identify the following. H2O(l) → H2O(s) question 2 options a negative ΔH and a negative ΔS a positive ΔH and a negative ΔS a negative ΔH and a positive ΔS a positive ΔH and a positive ΔS It is not possible to determine without more information. 3. Calculate ΔS°rxn for the following reaction. The S° for each species is shown below the reaction. C2H2(g) + H2(g) → C2H4(g) S°(J/mol∙K) 200.9 130.7 219.3 Question 4 options:...
Consider a reaction that has a positive AH and a negative As. Which of the following statements is TRUE? a. This reaction will be spontaneous only at high temperatures. b. This reaction will be spontaneous at all temperatures. c. This reaction will be nonspontaneous at all temperatures. d. This reaction will be nonspontaneous only at high temperatures. e. It is not possible to determine without more information.
- Part A Given the following balanced equation, determine the rate of reaction with respect to H . N2(g) + 3H2(g) - 2 NH (9) Rate = 1 AH 0 Rates AH 0 Rato + 1 HD 31 Rate = JAH 0 It is not possible to determine without more information Submit Request Answer
Part G Calculate AH for the following reaction: CH3OH(1) +O2(g) + HCOH(1) +H2O(1) Express the enthalpy in kilojoules to one decimal place. AC O O ? AH = Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part 1 Calculate AS for the following reaction: CHOH(1) +O2(g) + HCO-H1) +H2O(1) Express the entropy in joules per kelvin to one decimal place. IVO AED ROO? J/K AS = Submit Request Answer Part 1 From the values of AH°...
IN ILLIULIOL JU_SUN/Lab%20Exams/CHEZ101%2... Submit Answer kJ/mol Tries 0/2 7. Consider the following reactions: A-B AH = 272 kJ C-B AH = 36 kJ What is AH for A C ? It is possible that your answer could be either positive or negative. If it is negative, you must include the "minus" sign. Enter your answer as a decimal number. k] Tries 0/2 Submit Answer 8. Consider the following reactions: A + 2B - C + D AH = -224 kJ...
D Question 18 For the following example, identify the following. H2(1) H2(s) us and AG > 0 and at high temperature, at low temperature, the reaction is non reaction is spontaneous and AGO -- - at low temperature, the reaction is nonspontaneous and AG > O and at high temperature, the reaction is nonspontaneous and AG >0 It is not possible to determine without more informal at low temperature, the reaction is spontaneous and AG < 0 and at high...
Use the information provided to determine AH°rxn for the following reaction: AHºf (kJ/mol) 3 Fe2O3(s) + CO(g) → 2 Fe3O4(s) + CO2(9) AH°rxn = ? Fe2O3(s) 1 -824 Fe3O4(s)| -1118 CO(g) - 111 CO2(g) -394 0 +277 kJ 0 -111 kJ 0 -577 kJ 0 -47 kJ 0 +144 kJ Submit Request Answer
The standard enthalpy change for the reaction of SO3 (g) with H2O(l) to yield H2SO4 (aq) is AH° = -227.8 kJ. Part A Use the following information S(s) + O2(g) +SO2(g), AH° = -296.8kJ SO2(g) + 1 O2(g) +S03 (g), AH° = -98.9kJ to calculate AH; for H2SO4(aq) (in kilojoules per mole). [For H2O(l), AH = -285.8kJ/mol]. Express your answer using four significant figures. O AXO A o ai ? AH; = Submit Request Answer Provide Feedback
Part A Calculate AH (in kilojoules per mole) for benzene, C6H6, from the following data: 2C6H6(1) + 1502 (g)+12C02(g) + 6H2O(1) AH° = -6534kJ AH (CO2) = -393.5kJ/mol AH (H2O) = - 285.8kJ/mol O ALQ 6 A 0 2 ? AH = kJ/mol Submit Request Answer