Question

Consider the function f(1) = -2(1 - 3)2 (2x - 1) Answer all parts: (a)-(). (a) What is the degree of f(x)? The degree of f(3) is (b) Which of the following choices describe the end behavior of f(a)? The graph of f(2) acts O like 22 (ie both ends up) Olike -2" (ie, both ends down) like (i.e. left end down, right end up) O like --23 (i.e left end up, right end down) None of the above (c) State the 2 -- intercepts of f(x) and whether the graph crosses or touches the z-axis at that 2-intercept. Instructions: Type as a comma-separated list in the form (intercept, T or C) where T = touches, C = crosses. example: [1,1],[4,c). [-2, T) means this graph has x-intercepts at a = 1.2 = 4, and a = -2 and the gr crosses at = 4 and touches at the other two intercepts (d) The y-intercept is y =

Answer 1

6 f(x) = ---(2-3) -1) @ de degree = 4 - x (both ends down Hem) = 0 > U=0,3,1 [degree Hence noots are (0,2), (1,2), (311) y intenccptis fco) of factan (n-3) is a O 0 of exact number tunning points = 3 CS Scanned with CamScanner

Close-up view 10- у 5 -8 -2 -6 0 2 6 8 4 Maple plot -SI -10