Question

please select answer from options given in [] and are bold, there are 3 parts 1....

please select answer from options given in [] and are bold, there are 3 parts

1. An 9 kb circular plasmid is cut with the EcoRI restriction enzyme, and the reaction products are run on a DNA gel and stained with ethidium bromide. Bands of 1.0, 3.0 and 5.0 kb are seen.

2. When the same plasmid is cut with both the EcoRI and BamHI restriction enzymes (a double digest), bands of 1.0, 1.5, 3.0, and 3.5 kb are seen.

From these results, it can be concluded that        ["EcoRI", "BamHI"]         cuts within the                         ["3.0", "5.0", "1.0"]         kb                             ["BamHI", "EcoRI"]         band

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Answer #1

The correct statement is as follows :

From there results, can be concluded that BamHI cuts within the 5.0 Kb EcoRI band.

Explanation :

After Digestion with EcoRI, three bands are obtained with length of 1.0 Kb, 3.0 Kb and 5.0 Kb.

But when we do double digestion with EcoRI + BamHI, four bands are obtained with length of 1.0 Kb, 1.5 Kb, 3 Kb and 3.5 Kb.

Now if we compare both the results, we can easily conclude that 1.0 Kb and 3.0 Kb bands are identical. Also, upon closer inspection it is found that the two new bands of 3.5 Kb and 1.5 Kb add up to form 5.0 Kb. So it means that BamHI actually digests the 5.0 Kb fragment of (EcoRI digest) into two fragments of 3.5 Kb and 1.5 Kb.

This situation can be easily depicted with a simple diagram for even better explanation :

EcoRI Digestion: 1. okb 3.0kb 5.okb EcoRI + Bar HI Digestion: lookb 3.0kb 3.5kb 1-5 kb

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