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The following data are annual maximum floods Q (in m/s) for 7 years of record from 2005-2011. Using frequent factor method (p
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Answer #1

a)Log- Normal distribution is the special case of log-pearson distribution in which C_{s} = 0

so from following data we get

\bar{z} = 3.450754

\sigma_{z} = 0.1204

K2(when C_{s} = 0 ) = 2.576

z200= \bar{z} + K2\sigma_{z}

z200= 3.7609044

X200= Antilog (z200)

X200= 5766.4 m3/sec

b)

FROM THIS TABLE WE DETERMINE \sigma_{z}   

\sigma_{z} = 0.1204

C_{s} = \frac{N\sum (z-\bar{z} )^{3}}{(N-1)(N-2)\sigma _{z}^{3}}

C_{s}= -1.1644

from Log-pearson Type iii distribution

K2 = 1.201

z200= \bar{z} + K2\sigma_{z}

z200= 3.5954

X200= Antilog (z200)

X200= 3939.13 m3/sec

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