Question

Chapter 27, Problem 023 Partially correct answer. Your answer is partially correct. Try again. In the figure R1 = 130 Ω, R2 = 50 Ω, and the ideal batteries have emfs ε1 = 6.0 V, ε2 = 5.0 V, and ε3 = 4.0 V. Find (a) the current in R1, (b) the current in R2, and (c) the potential difference between points a and b.

R2 8 R w

Answer 1

given Ri= 1302 R2 = 502 R2 E, Gv {2=50 E2=4v I Ri Applying kirchoffing voltage sale to the epper Ez + E2 - & - Iz Ra=0 achene Ins currena Parsing R2 And through desishes kirchoffig voltage applying Ea IR, suche to the lower loop where Is to the corrent through resis for Ri C from equation @ Ez = I RI resistor of the current through Ri, e given By 5 V 3. A 1302 I, - Ez 3.846810 RI II, = 3.8468102A so, curnent an RI, A I= 3.846810 2 A from equation Ta R2 = Ezt Ez- & current in R2², Iss Eztę - & R2 (4 v) +(5v)-(ov) (502) I 2 = 0.06 A © The pokenti al difference between permudy at and was given by va - Vo = E + Ez = (50) +. (av) =9u Va-Vo= qu

Comment

All the parts has been answered