Thermo Question I have a reversible turbine, I am given T1,T2, and P1. I need to...
Thermo Question
I have a reversible turbine, I am given T1,T2, and P1. I need to find P2 using variable specific heat method. What equation would I use? also, the turbine takes in air. I know I would use steam tables for this part. Please let me know, thank you.
Homework Answers
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Thermo Question
I have a reversible turbine, I am given T1,T2, and P1. I need to...
Thermo Question I have a reversible turbine, I am given T1,T2, and P1. I need to...
Thermo Question I have a reversible turbine, I am given T1,T2, and P1. I need to find P2 using variable specific heat method. NOT THE CONSTANT SPECIFIC HEAT METHOD.What equation would I use? also, the turbine takes in air. I know I would use steam tables for this part. Please let me know, thank you. ***Note that the constant specific heat method is p2 = p1(T2/T1)^(k/k-1).. I am not talking about this method. Thanks.
Thermo one Question 5 A steam turbine generates energy in the form of work at the rate of 346.1...
Thermo one Question 5 A steam turbine generates energy in the form of work at the rate of 346.1 kJ/kg of steam. The steam at the inlet of the turbine is at 8 MPa, 480oC, and at a velocity of 163.5 m/s. The steam exits the turbine at 2 MPa, 240oC, and a velocity of 55.3 m/s. Heat transfer to the surroundings occurs where the outer surface (boundary) temperature is at 333.5oC. Determine the rate of entropy production (kJ/kg-K) within...
Thermodynamics- Gas mixture compression An ideal gas mixture at P1 and T1 is compressed in a...
Thermodynamics- Gas mixture compression
An ideal gas mixture at P1 and T1 is compressed in a piston
cylinder assembly first isothermally to P2 and then isentropically
(reversible and adiabatic) to T3. Assuming variable specific heats
(use ideal gas tables) determine the following given the properties
listed below.
--Given Values--
m_O2 (kg) = 0.38
m_N2 (kg) = 0.34
T1 (K) = 650
P1 (bar) = 1.32
P2 (bar) = 2.52
T3 (K) = 738
1. Determine the pressure (bar) at state...
2 moles of compressed air (diatomic gas) in a cylinder under the initial condition T1=573K p1=500kPa....
2 moles of compressed air (diatomic gas) in a cylinder under the initial condition T1=573K p1=500kPa. Found v1=0.019m^3 but can not remember then how to find V2. I think that it has something to do with T1=T2 condition then P2 can be found.... but stuck on how to proceed so with FULL written explanations with working would be much appreciated! All question info on practice exam below - note ISOTHERMAL EXPANSION. for part ii which after an explanation first. Two...
4. You are asked to perform thermodynamic analysis for a real gas that obeys the following...
4. You are asked to perform thermodynamic analysis for a real gas that obeys the following equation of state: aP where "a" and "b" are constants (the numerical value of these constants is not important for this problem). You also know that the real gas has the following molar heat capacity, which you can assume depends only on the temperature: Cpm = A + BT with T in kelvin. Also, 2aPaP2 Note that, since the gas is real, the relationship...
hi there! how did they get thst equation x1=am/p1? i dont know understand this paragraph. if...
hi there! how did they get thst equation x1=am/p1? i dont know
understand this paragraph. if someone could help that would be
great!
Cobb-Douglas Preferences For the case of Cobb-Douglas preferences it is easier to look at the algebraic! form of the demand functions to see what the graphs will look like. If u(11,12) = rm-9, the Cobb-Douglas demand for good 1 has the form 2 = am/pi. For a fixed value of Pı, this is a linear function of...
Hello, I am having trouble with part c of this question. Here is my work so far: The solution for part c states that a...
Hello, I am having trouble with part c of this question.
Here is my work so far:
The solution for part c states that a possible solution is (e^16
* 4^3) / 3!
I am having trouble understanding how they got e^16 or why they
decided to use e^(4^2) for M in the equation |f(x) - Tn(x)| <=
(M / (n + 1)!) * |x - 0|^(n + 1).
From my understanding, I have to maximize H^3(x) (i.e. 3rd
derivative...
NEED HELP BY TONIGHT PLEASE!!! Please help me, I am deeply confused in this class and...
NEED HELP BY TONIGHT PLEASE!!!
Please help me, I am deeply confused in this class and
trying so hard to understand. Please give detailed answers. I know
some of these might be confusing but your help will really help me
learn. The teacher requires very very detailed answers and he gives
nearly no (and I mean literally nearly zero) partial credit so I'm
dying here. Thank you sooooooo much, you have no idea.
Also, I am nearly leaglly blind and...
Someone please help me with this question. I am STRUGGLING with it! Their are four parts...
Someone please help me with this question. I am STRUGGLING with
it! Their are four parts to it!
Conservation of momentum [7] Conservation of energy [8] Where the prime represents the final velocities. These two equations simplify to [9] Note that the initial speed of the plastic, Vplastic = 0. In part I, you found that the speed and momentum of the steel ball at the bottom of the ramp are 1.38 m/s and pi = 3.141592653589793 msteelvsteel = 0.0367...
Hello. There is a question that I am stuck at, I have no clue how to...
Hello. There is a question that I am stuck at, I have no clue how to do it. It is LONG Accounting Transactions – Hair Today: Charlene Jackson’s business, Hair Today, has been operating in Auckland for the month of February 2020. It is set up as a sole trader. You call in for a haircut, and while she is trimming your hair, she tells you how business is going. “I think it’s going very well,” she says. “Last time...
Thermodynamics- Gas mixture compression
An ideal gas mixture at P1 and T1 is compressed in a piston
cylinder assembly first isothermally to P2 and then isentropically
(reversible and adiabatic) to T3. Assuming variable specific heats
(use ideal gas tables) determine the following given the properties
listed below.
--Given Values--
m_O2 (kg) = 0.38
m_N2 (kg) = 0.34
T1 (K) = 650
P1 (bar) = 1.32
P2 (bar) = 2.52
T3 (K) = 738
1. Determine the pressure (bar) at state...
4. You are asked to perform thermodynamic analysis for a real gas that obeys the following equation of state: aP where "a" and "b" are constants (the numerical value of these constants is not important for this problem). You also know that the real gas has the following molar heat capacity, which you can assume depends only on the temperature: Cpm = A + BT with T in kelvin. Also, 2aPaP2 Note that, since the gas is real, the relationship...
hi there! how did they get thst equation x1=am/p1? i dont know
understand this paragraph. if someone could help that would be
great!
Cobb-Douglas Preferences For the case of Cobb-Douglas preferences it is easier to look at the algebraic! form of the demand functions to see what the graphs will look like. If u(11,12) = rm-9, the Cobb-Douglas demand for good 1 has the form 2 = am/pi. For a fixed value of Pı, this is a linear function of...
Hello, I am having trouble with part c of this question.
Here is my work so far:
The solution for part c states that a possible solution is (e^16
* 4^3) / 3!
I am having trouble understanding how they got e^16 or why they
decided to use e^(4^2) for M in the equation |f(x) - Tn(x)| <=
(M / (n + 1)!) * |x - 0|^(n + 1).
From my understanding, I have to maximize H^3(x) (i.e. 3rd
derivative...
NEED HELP BY TONIGHT PLEASE!!!
Please help me, I am deeply confused in this class and
trying so hard to understand. Please give detailed answers. I know
some of these might be confusing but your help will really help me
learn. The teacher requires very very detailed answers and he gives
nearly no (and I mean literally nearly zero) partial credit so I'm
dying here. Thank you sooooooo much, you have no idea.
Also, I am nearly leaglly blind and...
Someone please help me with this question. I am STRUGGLING with
it! Their are four parts to it!
Conservation of momentum [7] Conservation of energy [8] Where the prime represents the final velocities. These two equations simplify to [9] Note that the initial speed of the plastic, Vplastic = 0. In part I, you found that the speed and momentum of the steel ball at the bottom of the ramp are 1.38 m/s and pi = 3.141592653589793 msteelvsteel = 0.0367...
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