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(a) 1.2 (10 mks each). In parts a) and b) below, assume px = $1, Py = $5, I = income = $21. Solve the U-max problem for each

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Answer #1

Solution:: In order to solve the problem, we need to find MRSxy & Budget Constraint Line

a) U = xy2 & px= 1, py= 5 , I = 21

To find MRS , Differentiate U function w.r.t x and then w.r.t y

U Max eqn is MUx / MUy = Px/Py

MRS = Differentiation of x / Differentiation of y

MUx = y2

MUy = 2yx

MRS = y2/2yx

Therefor, MRS = y/2x

Now set MRS with price ratio

price ratio = px/py

Price ratio = 1 / 5

MRS = px / py

Y / 2x = 1/5 ( Putting value of MUx, MUy and Px, Py )

y = 2x / 5 ( Substitute value of y into budget constraint)

Budget constratint = Px + Py = I

1.x + 5.y = 21

x + 5y = 21

Since y = 2x/5,

x + 5(2x/5) = 21

3x = 21

x = 7 ( Substitute this value into budget constraint )

Since x = 7 , Now Budget Constraint

7 + 5y = 21

Solving this give y = 2.8

b) U = x 1/3 y2/3 & px= 1, py= 5 , I = 21

MRS = px / py

MUx = 1/3 x-2/3y2/3

MUy = 2/3 x1/3 y -1/3

Solving these 2 equations we get,

y/2x = 1/5

5y = 2x

y= 2x / 5

Putting these value into budget constraint, we get

x + 5.(2x/5 ) = 21

3x = 21

x = 7 ( Substitute this value into budget constraint )

Since x = 7 , Now Budget Constraint

7 + 5y = 21

5y = 21-7

y = 14/5

Solving this give y = 2.8

Subtituting value of y gives value of

1.x + 5.y = 21

x + 5(2.8) = 21

x = 7

c) U = xy2 & px= P , py= 5 , I = 21

MUx = y2

MUy = 2yx

MUx/MUy = px / Py

y2  / 2yx = P / 5

y / 2x = P / 5

5/2(y) = Px

Substitute value of px into budget constraint

Budget constraint = xP + 5y = 21

5/2y + 5y = 21

15y = 42

y = 42 / 15

y = 2.8

therefor px = 7

x = 7/p

d) U = xy2 & px= 1, py= P, I = 21

MRS = Slope of Price

MUx = y2

Muy = 2yx

Px/py = 1/p

y/2x = 1/p

yp = 2x

Putting this value into Budget Constraint

X+py = 21

X + 2x = 21

3x = 21

x = 7

putting this value into budget constraint we get

7+py = 21

py = 21-7

py = 14

y = 14 /p

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