Solution:: In order to solve the problem, we need to find MRSxy & Budget Constraint Line
a) U = xy2 & px= 1, py= 5 , I = 21
To find MRS , Differentiate U function w.r.t x and then w.r.t y
U Max eqn is MUx / MUy = Px/Py
MRS = Differentiation of x / Differentiation of y
MUx = y2
MUy = 2yx
MRS = y2/2yx
Therefor, MRS = y/2x
Now set MRS with price ratio
price ratio = px/py
Price ratio = 1 / 5
MRS = px / py
Y / 2x = 1/5 ( Putting value of MUx, MUy and Px, Py )
y = 2x / 5 ( Substitute value of y into budget constraint)
Budget constratint = Px + Py = I
1.x + 5.y = 21
x + 5y = 21
Since y = 2x/5,
x + 5(2x/5) = 21
3x = 21
x = 7 ( Substitute this value into budget constraint )
Since x = 7 , Now Budget Constraint
7 + 5y = 21
Solving this give y = 2.8
b) U = x 1/3 y2/3 & px= 1, py= 5 , I = 21
MRS = px / py
MUx = 1/3 x-2/3y2/3
MUy = 2/3 x1/3 y -1/3
Solving these 2 equations we get,
y/2x = 1/5
5y = 2x
y= 2x / 5
Putting these value into budget constraint, we get
x + 5.(2x/5 ) = 21
3x = 21
x = 7 ( Substitute this value into budget constraint )
Since x = 7 , Now Budget Constraint
7 + 5y = 21
5y = 21-7
y = 14/5
Solving this give y = 2.8
Subtituting value of y gives value of
1.x + 5.y = 21
x + 5(2.8) = 21
x = 7
c) U = xy2 & px= P , py= 5 , I = 21
MUx = y2
MUy = 2yx
MUx/MUy = px / Py
y2 / 2yx = P / 5
y / 2x = P / 5
5/2(y) = Px
Substitute value of px into budget constraint
Budget constraint = xP + 5y = 21
5/2y + 5y = 21
15y = 42
y = 42 / 15
y = 2.8
therefor px = 7
x = 7/p
d) U = xy2 & px= 1, py= P, I = 21
MRS = Slope of Price
MUx = y2
Muy = 2yx
Px/py = 1/p
y/2x = 1/p
yp = 2x
Putting this value into Budget Constraint
X+py = 21
X + 2x = 21
3x = 21
x = 7
putting this value into budget constraint we get
7+py = 21
py = 21-7
py = 14
y = 14 /p
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