Question

8. A). Draw a Free energy diagram for each of the following reactions below. In your diagram indicate the Free energy of activation (ΔG° ± ) and the overall free energy change (ΔG°rxn)

B). Determine which side of the equilibrium is favored (products or reactants).

C). Calculate the relative equilibrium constant for each reaction. (Hint: use pKas)

NH2 O:NH NaOH HO F pka = 27 É ŅHz+ ŅH2 + + NaOH HO F É pKa = 4.6

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Answer #1

Solution Nh ng? TINH Naon + + 420 ن F pka = 27 ka = 10-27 NH2 NH3 (1) Naon + at Ho pka = 4.6 5 4.6 ka 2.511710 109 ka = 2.511will be towards reactant Side, (1) D= - RT In 10-4.6 Backward reaction will farour; Therefore equilibrium DO Aho = A9= + RT X

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