Question

Iz(max) 1 (max).IVes(max)-vzl-Ic(min) [Vps(min)-Vz] Vps(min)-0.90 z-0.1V ps(max) for Iz(min) = 0.11z(max) Vps (max) -V, R Iz(max)+1(min) R. • A Zener diode is connected in a voltage w + regulator circuit as shown in the Figure. The Zener voltage is Vz = 9V. V VZ • Determine the value of Ri such that the Zener diode remains in break down in the following two situations: If the load current varies from I = 50 to 500 mA and If the input voltage varies from V = 15 to 20 V. • Solve for :Iz(min) 0.312(max). BRL VE Enter your answer

Answer 1

Consider the circuit elhown A HIL + + Ri Izd Yve ata VI UL Vz=ay Now there will be theo equations, we have to Adue them to get ori Equation 1 When It is maxinum & Iz is mininum KOL at Node A Velmin) - 9 Iz (min) & Illmax) Ri 0.3 Iz(max) scom. - 15-9 Ri Izemin) + 500mA Ri Equation 2 : When It is minimum & Iz is maximum KCL at Node A Viimax) -9 Tremax) + Il(min) Ri lll Ri Iz (max) +50mA multiply with 0.3 on both sides 0.3 Iz (max) + 15mA 3.3 Ri

Equation Equation 6 → 3.3 R 500mA 15mA Ri 2.4 Ri 485mA Ri: 2.1 485 mA REE 5.567