Question

(c) A loaded zener regulator is shown in Figure 3. Given Vz= 5.1 V at, Iz = 49 mA, Izk= 1 mA, Zz = 72 and Izm= 70 mA. [Satu pengatur beban zener ditunjukkan di dalam Rajah 3. Diberikan V2 = 5.1 V, Iz = 49mA, Izx = 1mA, 2-7 dan Izm = 70mA.] i) Calculate the minimum and the maximum load currents for which the zener diode will maintain the regulation. [Kirakan nilai minima dan maksima arus beban untuk diod zener mengekalkan pengaturan.) [6 Marks/Markah] ii) Calculate the load regulation expressed as a percentage. [Kirakan aturan beban di dalam peratusan) [2 Marks/Markah]

Answer 1

Both parts has been solved and solution has been attached, find the same.

Q © sotm: Cis Giver circuit:- I R f t 22n IN473 R Vin=&v Given, V2= 5110, L2=49MA IZ K = ima Zz=7n Izmatoma co mini Renas Load cument Ilarin when and maximum load current = 'Ilirian 'Ilmar whei RL is min. That is Remin The circuit can be Jedrown as, R=22n int 1 rt of fz=uoma & Z=70 е Vin=8V Vo=v V2.5.1V Fig. Giver, Vz=5.10 Trien, Iz=49mA = 498103A kuz in Loop we have, IR. Via Iz. Zz - V₂ 8 - 22T - (49x163x7) - 5.1=0 - TI 2.557 Oi1162A 116.22 mA - 22

hence, I = 116.22 MA Load ciment, for max. Ilmax Iz should be voltage input The and current minimum as is const. hence, I = Izmir & Ilmaa. Const. Izmin 1 mA ² Izk = 1x103A Izle 2 I 2 = 1 mA we Izk Ther only Ilmas have From fig r 1 put have, If we apply kul in loop &- 22 I- Izk. zq - 5.1 = 22 Ia 8-501 1x163 Ах x I = 0.1315 A = 131.5 mA N I = Izkt Ilmax now, Ilmon 131.5-1 max. be Ilman - 130.5 mA And Load ciment For min road current Ilmin, Iz should = 70mA = 70.X 70.8103 Put This Izm and applying kulin loop , 8- 22 In 7 x Izm - 5.10 max: Iz = Izm now 219- 7x70x163 22 I = 22 I = 2141 I = 0.1095 A =log, 5 ma Any now, I= Izmt Ilmin mic-Load current, Imun = I-Iqm=:39.5 mA

(isy Load regulation =? - xloo % Load regulation Dvo DIL also, Iz Const hence I= Izt I ( Fraction - Change) DI2 + DI2 = 0» AIL=0 A I = 0 DI= Pte = DIZ 11 hence 1% load - regulation Dvo DIZ X loo T- From fig / V= Vot I₂ Zz avo DVOF AVZ + z. b Iz but V₂ = Const @V2 =o) hence, Avo= Zz Iz) DVO= (A Iz) • Zz hence, it load - regulation, DVO DIZ X 1oo E-Zz -7% on, Load degulation 7% And